6y^2+17y-37=0

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Solution for 6y^2+17y-37=0 equation: 



6y^2+17y-37=0

a = 6; b = 17; c = -37;
Δ = b2-4ac
Δ = 172-4·6·(-37)
Δ = 1177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{1177}}{2*6}=\frac{-17-\sqrt{1177}}{12}
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{1177}}{2*6}=\frac{-17+\sqrt{1177}}{12}
$

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